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resolve the age dispute!

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resolve the age dispute!

by ashish1354 » Mon Feb 16, 2009 11:17 am
1. Roy is now 4 years older than Erik and half of that amount older than Iris. If in 2 years, Roy will be twice as old as Erik, then in 2 years what would be Roy’s age multiplied by Iris’s age?

(a) 8
(b) 28
(c) 48
(d) 50
(e) 52
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by truplayer256 » Mon Feb 16, 2009 11:34 am
R= Roy's Age
E=Erik's age
I=Iris's age

R=E+4
R=2+I
R+2=2(E+2)
E+6=2E+4
E=2
R=6
I=4
In 2 years, Roy's age will be 8 and Iris's age will be 6.
8 x 6=48 C
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by DeepakR » Mon Feb 16, 2009 6:45 pm
[quote="truplayer256"]R= Roy's Age
E=Erik's age
I=Iris's age

R=E+4
R=2+I
R+2=2(E+2)
E+6=2E+4
E=2
R=6
I=4
In 2 years, Roy's age will be 8 and Iris's age will be 6.
8 x 6=48 C[/quote]

I guess its a typo from truplayer256. The 2nd equation would be like,

R=I+(I/2) instead of R=2+I. The rest of them are perfect.
R=E+4 and R+2=2(E+2) hence E=2 and R=6 and I=4

In 2 yrs R+2= 8 and I+2=6 hence R*I= 8*6= 48

-Deepak
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by truplayer256 » Mon Feb 16, 2009 6:59 pm
No, Deepak, it isn't really a typo. R=2+I really represents half of 4 plus Iris's age since the question states that "Roy is now 4 years older than Erik and half of that amount older than Iris." In this case, that amount is 4.
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