-
jimmiejaz
- Master | Next Rank: 500 Posts
- Posts: 207
- Joined: Sun Mar 11, 2007 6:16 pm
- Location: Mumbai
- Thanked: 11 times
Hi guys,
I am stuck at this problem. I can figure this with the basic weighed avges but i want to know how to solve this problem if we take 100 and 200 gallons as 0 and 100 respectively and i am getting 35% instead of 30%.
Wat's the fault in my approach. please explain.
Mixture M consists of 65% water and 35% ethanol. Mixture N
consists of 80% water and 20% ethanol. If 200 gallons of
Mixture M is combined with 100 gallons of Mixture N, what
percent of the resulting solution is ethanol?
Approach one:
(.35*200+.2*100)/300 = 30%
Approach 2:
(.35*100+.2*0)/100 = 35%
why is the answer diff this time?
I am unable to figure out!!!!
I am stuck at this problem. I can figure this with the basic weighed avges but i want to know how to solve this problem if we take 100 and 200 gallons as 0 and 100 respectively and i am getting 35% instead of 30%.
Wat's the fault in my approach. please explain.
Mixture M consists of 65% water and 35% ethanol. Mixture N
consists of 80% water and 20% ethanol. If 200 gallons of
Mixture M is combined with 100 gallons of Mixture N, what
percent of the resulting solution is ethanol?
Approach one:
(.35*200+.2*100)/300 = 30%
Approach 2:
(.35*100+.2*0)/100 = 35%
why is the answer diff this time?
I am unable to figure out!!!!
What if i have not yet beat the beast, I know i will beat it!!!!!!!!
