Anurag@Gurome wrote:
Statement 2: |a - b| = distance between a and b = absolute value of 5 units = 0.625
Hence, absolute value of 2 b = absolute value of 2 units = (0.625/5)*2 = 0.250
As b lies on the left of zero on the number line, b = -0.250
Sufficient
The correct answer is D.
Wow that was quick. Thanks Anurag.
Well here's my reasoning for B because of which I selected only A as the answer.
(2). |a - b| = 0.625
If i open the absolute values, then this will be:-
a - b = 0.625 and a - b = -0.625
We know that a and b are on the negative side of the number line i.e < 0
I am taking x as an interval
So, |-7x - (-2x)| = 0.625 and |-7x - (-2x)| = -0.625
Solving for 1st
|-7x + 2x| = 0.625
|-5x| = 0.625
5x = 0.625
x = 0.125
b = 2x = 2 * 0.125
b = 0.25
Now solving for 2nd
|-7x - (-2x)| = -0.625
|-7x + 2x| = -0.625
|-5x| = -0.625
5x = -0.625
x = -0.125
Now, b = 2x = 2*(-0.125)
b = -0.25
We have got 2 values for B
The absolute value of |a - b| = 1 always gives 2 results
a - b = 1 and a - b = -1
This was the reason I selected A. So, my method was not correct ?
Regards
Vinni