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Combined inequality and absolute question

Expert replies
Source: — Data Sufficiency |

by ceilidh.erickson » Thu Apr 13, 2017 4:17 pm
What is the source of this question? First of all, it's a copyright violation to post content without citing the original source. Secondly, this question is incorrect as posted (not to mention unrealistically labor-intensive).

When you're given absolute values with inequalities, you have to establish different cases for POSITIVES v. NEGATIVES.

First, let's interpret the given: |x - a| < |x - b|
Test cases for x, a, and b that fit:
Image

etc. (You wouldn't really need to test all of these, nor is this exhaustive. I'm just giving several examples).

We need more information on whether x, a, and b are positive or negative, and/or information about their relative sizes before we know anything concrete.

Now interpret the question: a < ba < b?

When would the product of two numbers be greater than one number, but smaller than the other?
- Neither of the numbers could be 0 or 1, because then 2 of those values would be equal.
- They can't both be positive integers, because then ab would be greater than a or b.
- a could be a fraction between 0 and 1, and b could be greater than 1. ab then would be in between
- They cannot both be negative, since ab would then be positive
- It could be that a is negative less than -1, and b is a positive fraction btw 0 and 1

There is not one simple way to rephrase this question - there are a variety of scenarios to consider.

1. ab < 0

This tells us that one of the variables is negative, the other is positive. With the given information, several of our examples from the given information fit:
x = 10, a = 3, b = -2
--> a < ab < b ?
--> 3 < -6 < -2
--> NO.

x = 1/8, a = -1/8, b = 7/8
--> a < ab < b ?
--> -1/8 < -7/64 < 7/8
--> YES.

Insufficient.


2. For all x > 0, |x - a| = |x| + |a|

This doesn't tell us anything about b, so we can tell from a glance that it's insufficient.

But, here's how we would interpret: For all x > 0, |x - a| = |x| + |a|

Image

Since x must be positive, a must be either negative or 0.

Together:
(1) a and b have different signs (one negative, one positive)
(2) x is positive, a </= 0

See what scenarios remain from our original analysis:

Image

Two of our original scenarios work.
#1: a = -3, b = 8
--> a < ab < b ?
--> -3 < -24 < 8
--> No.

#2: a = -1/8, b = 7/8
--> a < ab < b ?
--> -1/8 < -7/64 < 7/8
--> Yes.

(1) and (2) together are INSUFFICIENT. The correct answer should be E.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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by GMATGuruNY » Fri Apr 14, 2017 5:32 am
Mo2men wrote:2. For all x>0, |x−a|=|x|+|a|
The intent here is unclear.
The portion in red seems to imply the following:
If x>0, then |x−a|=|x|+|a|.
If x≤0, then it does NOT have to be true that |x−a|=|x|+|a|.
Since the intended meaning is unclear, I would ignore this problem.
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by ceilidh.erickson » Sun Apr 23, 2017 6:01 am
Mo2men - following up. Please post the source of this question.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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