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by schakiiieee » Tue Mar 25, 2008 7:59 pm
Hi,

my 1st reply here but I hope it helps:

n!/(k!(n-k)!) for n = 5 (5 women) and k = 3 (3 in one group) gives you the number of possibilites of women in one group.

12 employees, 5 women --> 7 possible males in a group. Thus, multiply the number of possibilites of women in one group with the number of males.

-->

5!/(3!*(5-3)!) * 7 = 70.

There should be 70 possible groups.
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by camitava » Tue Mar 25, 2008 8:30 pm
Agree with schakiiieee!
Correct me If I am wrong


Regards,

Amitava
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