Data Sufficiency

Of the 200 members of certain association, each member who speaks german also speaks english. and 70 members speak only spanish. no member speaks all 3 languages. how many of the members speaks 2 of 3 languages ?
1. 60 members speaks only english
2. 20 members do not speak any of the three languages

OA = C
I was able to compute the solution :
(u = Union and n = Intersection)
E u G u S = E + G + S - (E n S) - (S n E) - (S n G) + (E n G n S) + {Who speak 0 languages}
E n S = G
(E n G n S) = 0
{Who speak 0 languages} = 20
E= 60
S=70

Therefore, people speaking two languages = 200-150 = 50


My question is that if every member who speaks English also speaks German (or vice-versa), they cannot speak Spanish because members who speak all 3 languages = 0. For instance, if in a room, I have 100 people of which 50 speak English and Spanish, and 0 who speak all three languages. It means that I will have only 50 people who speak two languages. I cannot have anyone from (English / German) group speak Spanish because he will end up speaking three languages. Any thoughts?

Thanks