IMO C
Each team gets to play a total of 10 games. Whenever a team wins, another team loses. Therefore, the # of lose equal to # of win. The total# of games are 6p2*2=60, so there are 30 loses as well as 30 wins. If you add up all the given wins, u will get 24. total#of wins 30-24=6-wins for X. Same drill, u can get the #of lose for X, which is 4. In case GMAT ask u the same question in a different way.
Please let me know in case I am wrong.
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jeffxujian
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I agree with u that the answer is 6 but not convinced that the number of matches played were 60
if team a played match against team b......its the same as team b playing against team a.....so its combinations rahter than permutations.
thus in IMO the number of games played is 30.thus if number of wins are 24 from a total of 30 matches played........x must have won 6 matches.
let me know if i am wrong.
if team a played match against team b......its the same as team b playing against team a.....so its combinations rahter than permutations.
thus in IMO the number of games played is 30.thus if number of wins are 24 from a total of 30 matches played........x must have won 6 matches.
let me know if i am wrong.
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cramya
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All teams play the same number of matches. Take A it can play 5 games with the other team.
Similarly th3 6 teams can each play 5 matches making the total number of matches to be 30.
30- (numbers given for matches won by the various teams but x) = 6
x won 6 games
Similarly th3 6 teams can each play 5 matches making the total number of matches to be 30.
30- (numbers given for matches won by the various teams but x) = 6
x won 6 games
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cramya
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I think we may all be wrong with number 30. I agree with jeffxujian.
A plays 10 games, B play 10 games since each team plays the other team exactly 2 times.
Since we are given the number of wins column and not number of losses like jeffxujian pointed out it will be6 since number of wins must equal number of losses
A plays 10 games, B play 10 games since each team plays the other team exactly 2 times.
Since we are given the number of wins column and not number of losses like jeffxujian pointed out it will be6 since number of wins must equal number of losses
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bluementor
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The total number of matches = 30
There are 2 ways to know this:
1) Think of the 2 matches for each pair of teams as A plays B and B plays A.
Therefore total number of matches = 6P2 = 30
2) The other way is that we reduce the problem where each pair of the teams play each other only once:
i.e. A plays B and B plays A is the same (arrangement is not a concern)
Total number of matches if each pair play each other only once = 6C2 = 15
Therefore, the total number of matches if each pair play each other twice = 6C2 * 2 = 30
Hope the above helps.
BlueMentor
There are 2 ways to know this:
1) Think of the 2 matches for each pair of teams as A plays B and B plays A.
Therefore total number of matches = 6P2 = 30
2) The other way is that we reduce the problem where each pair of the teams play each other only once:
i.e. A plays B and B plays A is the same (arrangement is not a concern)
Total number of matches if each pair play each other only once = 6C2 = 15
Therefore, the total number of matches if each pair play each other twice = 6C2 * 2 = 30
Hope the above helps.
BlueMentor
