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GMAT PREP : Difficult PS

Expert replies
by Darshan.D » Sat Sep 13, 2008 12:06 am
Hey guys,
Came across the following questions in GMAT PREP. PLz help...

PS =>
1. Which of the following inequalities has a solution set that, when graphed on number line, is a single line segment of finite length?
1. x^4 >= 1
2. x^3 <= 27
3. x^2 >= 16
4. 2 <= mod “x” <= 5
5. 2 <= 3x + 4 <= 6
Answer = 5

2. If n is a multiple of 5 and n=(p^2)q, p and q are prime numbers, which of the following must be a multiple of 25?
1. p^2 * q^2
2. p^3 * q
3. pq
4. p^2
5. q^2
Answer = 1 (p^2 * q^2)

3. If x > y^2 > z^4
z > y > x could be true?
Answer = Yes (How???)

4. There are 4 senior managers & 6 junior managers. How many diff 3 member groups can formed in which at least one member in group is a senior manager?
1. 48
2. 100
3. 120
4. 288
5. 600
Answer = 100

5. Alice’s takehome pay last yr was same each month, and she saved same fraction each month from her takehome pay. The total amount she saved at end of tht yr was 3 times amount of the portion of her monthly takehome pay that she did not save. If all the money she saved last yr was from her takehome pay, wat fraction of her takehome pay did she save each month?
½, 1/3, ¼, 1/5, 1/6

Answer = 1/5 ( i get 1/4 )

Also, any recommendations for improvement in problems involving Number Properties & permutations & combinations ?

Thanks in advance
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Source: — Problem Solving |

by alescau » Sun Sep 14, 2008 2:05 pm
1. Ans. 5 is a sloped line, therefore it is the answer. Eliminate the other answers.

2. Since 5 is a prime, q or p must also be 5. If we squared the one that is 5, we would have a multiple of 25. Since we don't know which one it is, p^2*q^2 covers both cases.

3. Numbers btw 0 and 1 may satisfy the condition. The larger the power the smaller they get.
Ex. x=0.6 y=0.7 z=0.8
x=0.6 y^2=0.49 z^4=0.41..

4. dunno this topic

5. Takehome/mnth = x
Saved/mnth = yx
Saved/yr = 3 (Takehome/mnth - Saved/mnth) = 3 (x - yx)
Saved/yr = 12 Saved/mnth
12yx = 3 (x - yx) = 3x - 3yx
15yx = 3x
y = 1/5
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ans 4:

by vr4indian » Tue Sep 16, 2008 6:17 am
total members = 10

Total way to select 3 members team from 10 = 10 c3 = 120

Total way to select 3 members team from 6 jr = 6c3* = 20
(*team with only jr member)

Now just substract 120-20 = 100 . that is all team - only jr team = team which has atleast 1 sr member

Thanks
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