Any ideas how to solve the following question (OA is D)?
Thanks in advance
Thanks in advance
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GMAX
The area of the equilateral triangle will be [(t^2)sqrt(3)]/4.
The area of the square will be s^2.
The two are equal, so you get that:
[(t^2)sqrt(3)]/4 = s^2
(t^2)sqrt(3) = 4(s^2) - apply sqrt andd get:
t*(fourth degree root of 3) = 2s.
This makes t = 2s/(fourth degree root of 3) and t:s 2:(fourth degree root of 3).
