given below r the answers for the 2nd & 3rd

2.
Car can travel -360 miles with 12 gallons
So gasoline needed for 250 miles is 25/3 gallons
Fraction of gasoline used is : (25/3)/12
=25/36


3.

The answer should be bet. 15 nd 200.
i.e n*(n+1) >15 the smallest no tat satisfies this is 4 (4*5=20)
nd n*(n+1)<200 the largest no tat satisfies this is 13 (13*14=182)
14 cannot be the answer coz (14*15=210) which does not satisfy the condition

preetha_85 wrote:given below r the answers for the 2nd & 3rd

2.
Car can travel -360 miles with 12 gallons
So gasoline needed for 250 miles is 25/3 gallons
Fraction of gasoline used is : (25/3)/12
=25/36


3.

The answer should be bet. 15 nd 200.
i.e n*(n+1) >15 the smallest no tat satisfies this is 4 (4*5=20)
nd n*(n+1)<200 the largest no tat satisfies this is 13 (13*14=182)
14 cannot be the answer coz (14*15=210) which does not satisfy the condition

Okay, It might be late, but I don't understand how you are getting the 25/3 ?!? Isn't 250/30 giving you the amount of gasoline consumed?

EDIT: NVM you removed the 0 from each number. But see I did 25/3=8.33/12=wich reduces to 2/3..how did you know to put muliple the 12*3 to get 25/36??

I understand number 3, thanks! I didn't even think about turning it into a equation like that.

ajmoney09 wrote: Okay, It might be late, but I don't understand how you are getting the 25/3 ?!? Isn't 250/30 giving you the amount of gasoline consumed?

EDIT: NVM you removed the 0 from each number. But see I did 25/3=8.33/12=wich reduces to 2/3..how did you know to put muliple the 12*3 to get 25/36??

I understand number 3, thanks! I didn't even think about turning it into a equation like that.

This is how we get 25/3 --> it was informed in the question that the car travels for 5 hour at 50 mph. From this information we calculate the distance in 5 hour = 5 hour X 50 mph = 250 miles

And the car consumes 1 gallon of gasoline every 30 miles.

So, in order to calculate the amount of gasoline used, we have to divide 250 miles/30 miles = 25/3 gallon (this is the fuel needed for 5 hour travel at 50 mph)

The fraction is (25/3)/12 = 25/36

Hope this helps...

Enjoy your day...

ajmoney09 wrote:
No idea... please help

All OA are int he bottom right of each question...
Thanks, and Please help.

We just have to find how many values lie above 8.1 i.e the mean and below 8.1.


Standard deviation = 0.3

1.5 standard deviation = 0.45

8.1 + 0.45 = 8.55

8.1-0.45 = 7.65

Any value which fall in with in this range will be counted. Therefore only one value is left out i.e. 7.51.


I guess others have done a pretty good job answering the other questions.

Let me know if you still have any doubts.

parallel_chase wrote:

ajmoney09 wrote:
No idea... please help

All OA are int he bottom right of each question...
Thanks, and Please help.

We just have to find how many values lie above 8.1 i.e the mean and below 8.1.


Standard deviation = 0.3

1.5 standard deviation = 0.45

8.1 + 0.45 = 8.55

8.1-0.45 = 7.65

Any value which fall in with in this range will be counted. Therefore only one value is left out i.e. 7.51.


I guess others have done a pretty good job answering the other questions.

Let me know if you still have any doubts.

How did you get .45?

(0.3)(1.5) = .45??

ajmoney09 wrote:

parallel_chase wrote:

ajmoney09 wrote:
No idea... please help

All OA are int he bottom right of each question...
Thanks, and Please help.

We just have to find how many values lie above 8.1 i.e the mean and below 8.1.


Standard deviation = 0.3

1.5 standard deviation = 0.45

8.1 + 0.45 = 8.55

8.1-0.45 = 7.65

Any value which fall in with in this range will be counted. Therefore only one value is left out i.e. 7.51.


I guess others have done a pretty good job answering the other questions.

Let me know if you still have any doubts.

How did you get .45?

(0.3)(1.5) = .45??

Yes, you can also look at this way.

if 1 apple costs $3

how much would it cost for 1.5 apple.