RATIO AND PROPORTION

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RATIO AND PROPORTION

by sayanpaul » Wed Jul 03, 2013 3:39 am
Suppose y varies as the sum of two quantities of which one varies directly as x and the other inversely as x. If y = 6 when x = 4 and y = 10/3 when x = 3, then the relation between x and y is:

A. x = y+4
B. y = 2x+(8/x)
c. y = 2x-(8/x)
D. y = 2x-(4/x)
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by GMATGuruNY » Wed Jul 03, 2013 5:43 am
sayanpaul wrote:Suppose y varies as the sum of two quantities of which one varies directly as x and the other inversely as x. If y = 6 when x = 4 and y = 10/3 when x = 3, then the relation between x and y is:

A. x = y+4
B. y = 2x+(8/x)
c. y = 2x-(8/x)
D. y = 2x-(4/x)
When x=4 is plugged into the correct answer choice, y=6.
Only C works:
y = 2x - (8/x) = 2*4 - (8/4) = 6.

The correct answer is C.
Last edited by GMATGuruNY on Thu Jul 04, 2013 7:36 am, edited 1 time in total.
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by ganeshrkamath » Thu Jul 04, 2013 2:58 am
sayanpaul wrote:Suppose y varies as the sum of two quantities of which one varies directly as x and the other inversely as x. If y = 6 when x = 4 and y = 10/3 when x = 3, then the relation between x and y is:

A. x = y+4
B. y = 2x+(8/x)
c. y = 2x-(8/x)
D. y = 2x-(4/x)
y = ax + b/x
6 = 4a + b/4 ___ (1)
10/3 = 3a + b/3 ___ (2)
from (1) 24 = 16a + b
from (2) 10 = 9a + b
14 = 7a
a = 2
b = -8

y = 2x - 8/x

So C.