[email protected] wrote:Hi Experts,
COuld you please suggest an easier way to solve this, Should I apply the similar tirangle theorem?
∆ABC = ∆ABD?
Since ∆ABC= (1/2)(AC)(BC) and ∆ABD = (1/2)(AB)(AD), we get:
(1/2)(AC)(BC) = (1/2)(AB)(AD)?
Question rephrased: Does (AC)(BC) = (AB)(AD)?
Statement 1: (AC²) = 2(AD²)
Thus:
AC = √2(AD).
No information about BC and AB.
INSUFFICIENT.
Statement 2: ∆ABC is isosceles
In an isosceles right triangle, the sides are proportioned x : x : x√2.
Since the length of the hypotenuse of ∆ABC is equal to √2 times the length of each leg, we get:
AB = √2(BC)
BC = (AB)/√2.
No information about AD.
INSUFFICIENT.
Statements combined:
Multiplying AC = √2(AD) by BC = (AB)/√2, we get:
(AC)(BC) = √2(AD) * (AB)/√2
(AC)(BC) = (AD)(AB).
SUFFICIENT.
The correct answer is
C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
