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help on this

Expert replies
by alltimeacheiver » Fri Feb 11, 2011 1:48 am
The infinite sequence a1, a2,..., an,... is such that a1 = 2, a2 = -3, a3 = 5, a4 = -1, and an =
an-4 for n > 4. What is the sum of the first 97 terms of the sequence?
A. 72
B. 74
C. 75
D. 78
E. 80
------------------------------------------------------------------------------------------------------------
If x and y are positive integers and 1 + x + y + xy = 15, what is the value of x + y?
A. 3
B. 5
C. 6
D. 8
E. 9
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Source: — Problem Solving |

by Anurag@Gurome » Fri Feb 11, 2011 4:54 am
Question 1:

It is given that an = an-4 for n > 4 so a5 = a1, a6 = a2, a7 = a3, a8 = a4

Therefore, the sequence is 2, -3, 5, -1, 2, -3, 5, -1, ...

It can be seen that the sum of 1st 4 terms = 2 + (-3) + 5 + (-1) = 3
Since the sequence repeats itself in sets of 4, so the sum of 1st 96 terms = 3 * 24 = 72
Hence, sum of 1st 97 terms = 72 + 2 = 74

[spoiler]The correct answer is B.[/spoiler]
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by Anurag@Gurome » Fri Feb 11, 2011 5:01 am
1 + x + y + xy = 15
1 + x + y(1 + x) = 15
(1 + x)(1 + y) = 15

It is given that x and y are positive integers and 15 can be expressed as a multiple of 2 integers: (1, 15) and (3, 5).
If (1 + x)(1 + y) = 1 * 15 implies 1 + x = 1 and 1 + y = 15 or x = 0 and y = 14
So, x + y = 14
If (1 + x)(1 + y) = 3 * 5 implies 1 + x = 3 and 1 + y = 5 or x = 2 and y = 4
So, x + y = 6
From the above two values of x + y, 6 is the only choice.

[spoiler]The correct answer is C.[/spoiler]
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by gtestprep » Fri Feb 11, 2011 5:02 am
alltimeacheiver wrote: If x and y are positive integers and 1 + x + y + xy = 15, what is the value of x + y?
A. 3
B. 5
C. 6
D. 8
E. 9
First factor 1 + x + y + xy = 15. You get (1 + x)(1 + y) = 15.
Because it is stated that x and y are both positive integers, the only possible values could be [(1,15) , (3,5)]
if (x,y) = (1,15) or (15,1) then x + y = 14. However, this means that either one of x or y will have to take the value of 0 which is not acceptable based on the conditions stated in the question. So, that leaves us only with the possibility of (x,y) = (3,5) or (5,3) then x + y = 6. So the answer is C.
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by Night reader » Fri Feb 11, 2011 6:05 am
:) https://www.beatthegmat.com/help-on-this ... tml#339273
Anurag@Gurome wrote:1 + x + y + xy = 15
1 + x + y(1 + x) = 15
(1 + x)(1 + y) = 15

It is given that x and y are positive integers and 15 can be expressed as a multiple of 2 integers: (1, 15) and (3, 5).
If (1 + x)(1 + y) = 1 * 15 implies 1 + x = 1 and 1 + y = 15 or x = 0 and y = 14
So, x + y = 14
If (1 + x)(1 + y) = 3 * 5 implies 1 + x = 3 and 1 + y = 5 or x = 2 and y = 4
So, x + y = 6
From the above two values of x + y, 6 is the only choice.

[spoiler]The correct answer is C.[/spoiler]
Join the discussion