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by rabab » Thu Oct 16, 2008 6:35 am
A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?

a) 1/4
b) 3/8
c) 1/2
d) 5/8
e) 3/4

Anyone pls?
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by dmateer25 » Thu Oct 16, 2008 6:59 am
Here are the possible outcomes for the balls:

E+E+E = Even
E+E+O = Odd
E+O+O = Even
E+O+E = Odd
O+E+E = Odd
O+E+O = Even
O+O+E = Even
O+O+O = Odd


4 possibilities it will be even and 4 that it will be odd

so 4/8 that it will be odd

1/2 that it will be odd

I go with C

OA?
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by rabab » Thu Oct 16, 2008 7:06 am
Damn! I was close!

Thanks. The answer indeed is C.
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