You have to plug in for this one.vinviper1 wrote:Thanks!
I'll try to explain the question as clearly as I can. If f(x)=f(1-x), that means that wherever x works in an equation, you will get the same answer by substituting (x) with (x-1). This question does not give you a clear road map on what the answer will be (it could be anything), so you have to reference the answers TO FIND the answer. Below are the ways you would set up each answer:
A. 1-(1-x)
B. 1-[(1-x)^2]
C. [(1-x)^2]-[1-(1-x)]^2
D. [(1-x)^2][1-(1-x)]^2
E. (x-1)/[1-(x-1)]
Once again, all I am doing is replacing all (x)s with (x-1)s. If you solved each equation, you will find that D is the one that will give you the original equation after substituting (x-1) for x.
Hope this makes sense.

















