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Source: — Data Sufficiency |

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by inittowinit » Fri Aug 05, 2011 8:47 am
IMO C.

Statement 1. X can be less the 0.5 and still make the statement true, such as x = 0.1, 80<620
Insufficient

Statement 2. X can be anywhere 0.51X to 1,1.5,2, 2.46643 etc and still make the statement true. Again Insufficient.

Taking the two statements together, X is somewhere between .51 < X < .78

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by gmatboost » Fri Aug 05, 2011 11:05 am
Let's give it a shot without finding the exact decimal values of the fractions.

Statement 1:
800x < 620
x < 620/800
x < 62/80
x < 31/40

You should recognize that 31/40 is just a little more than 3/4.
[spoiler]This means x may or may not be between 0.5 and 0.9. Insufficient.
[/spoiler]
Statement 2:
1200x > 620
x > 620/1200
x > 62/120
x > 31/60

You should recognize that 31/60 is just a little more than 1/2.
This means x may or may not be between 0.5 and 0.9. Insufficient.

Combined:
[spoiler]0.5 < 31/60 < x < 31/40 < 0.9. Sufficient.[/spoiler]
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by gmatblood » Fri Aug 05, 2011 1:04 pm
IMO: C

from 1)x can be anywhere between 0.1 and 0.7xxx
from 2)x can be anywhere betwen 0.5xxxx and 1

combining both x can be between 0.5xx and 0.7, sufficient

Hence C

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by krishnasty » Sat Aug 06, 2011 1:45 am
IMO C

From 1,
x < .77
INSUFFICIENT

From 2,
x > .51
INSUFFICIENT

Combining both, .77>x>.51
Hence, SUFFICIENT
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