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Is this the correct way of solving !!

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by su_gmat » Mon Feb 13, 2012 10:33 pm
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean,
and the largest number in the set is equal to 20 more than three times the smallest number, what is the
largest possible range for the numbers in the set?
1) 78 2) 77 3) 66 4) 55 5) 52


Answer : 1) 78

since, it says median of the set is equal to the mean hence , we may assume that it can be in AP series.

lets take the series R1,R2,R3,R4,R5 ; Median is 55 hence the R3=55 either in ascending or the decending order.

R5=3R1+20 ------equation 1

so we can Imply Range=R5-R1 , Where R5 is max value and R1 is the least in the set of 5 numbers.

therefore from equation 1

R5-R1=2R1+20
take the option 1) 78
we can see the
78=2R1+20
R1=29

out of all the given choices , the 78 is the biggest possible range which gives R5=107 and R1=29
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Source: — Problem Solving |

by Jim@StratusPrep » Tue Feb 14, 2012 6:26 am
It is somewhat right. You come to the right answer, but you fail to check if your answer is possible.

The sequence ends up like this:

R1, R1, 55, 55, 3R1+20 and the sum equals 275 so you can solve for R1. See below for why this is the sequence.

You already had values for R1, R3 and R5, so you just need R2 and R4. In order to maximize the range you must minimize these values. So R4 is limited by the median and R2 is limited by R1
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