Yes.
Your problem is that you are not reading the question thoroughly. It is not 1/4 of the total distance, but rather 1/4 of the distance remaining.
If she drives half the distance, then 1/4 of the remaining half, she has travelled 5/8 of the total distance. The remaining 3/8 = 120. Solve for total distance -
120/3 * 8 = 320
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cant find what is wrong
Source: Beat The GMAT — Problem Solving |
Let x miles be the total distance.
Maria stopped after travelling half the distance i.e. x/2 miles
Thene she stopped after travelling 1/4th of the remaining distance(Since Maria has travelled x/2 miles already the remaining would be
x-x/2) and 1/4 the of that is 1/4(x-x/2). Then she travels 120 miles.
There x/2 + 1/4(x-x/2)+120 = x
Solving for x we get x = 320
Check:
320/2 = 160 Remaining distance = 1/4(320-160) = 40 Then 120
160+40+120 = 320
Maria stopped after travelling half the distance i.e. x/2 miles
Thene she stopped after travelling 1/4th of the remaining distance(Since Maria has travelled x/2 miles already the remaining would be
x-x/2) and 1/4 the of that is 1/4(x-x/2). Then she travels 120 miles.
There x/2 + 1/4(x-x/2)+120 = x
Solving for x we get x = 320
Check:
320/2 = 160 Remaining distance = 1/4(320-160) = 40 Then 120
160+40+120 = 320
Let x miles be the total distance.
Maria stopped after travelling half the distance i.e. x/2 miles
Then she stopped after travelling 1/4th of the remaining distance.Since Maria has travelled x/2 miles already the remaining would be
x-x/2 and 1/4 th of that is 1/4(x-x/2).
Then she travels 120 miles.
Therefore all 3 above put together must be equal to the total destination miles
i.e.
x/2 + 1/4(x-x/2)+120 = x
Solving for x we get x = 320
Check:
320/2 = 160 Remaining distance = 1/4(320-160) = 40 Then 120
160+40+120 = 320
Maria stopped after travelling half the distance i.e. x/2 miles
Then she stopped after travelling 1/4th of the remaining distance.Since Maria has travelled x/2 miles already the remaining would be
x-x/2 and 1/4 th of that is 1/4(x-x/2).
Then she travels 120 miles.
Therefore all 3 above put together must be equal to the total destination miles
i.e.
x/2 + 1/4(x-x/2)+120 = x
Solving for x we get x = 320
Check:
320/2 = 160 Remaining distance = 1/4(320-160) = 40 Then 120
160+40+120 = 320
i solved this using backsolving, fairly easy, but easy to lose track of what they are really asking for, when doing the calculations.
Is it a GMATPrep question? If so, please state that explicitly in the topic. I'm sorry if it is not.
what i try doing for questions like these is drawing a line and
marking point along, of course following the questions instructions !!
"not draw to scale nor .. nor even close.. but you can have an idea...
l--------------l----l----l----l----l
1st half l l
here she stops
l
l here is 1/4 of the remaing distance...
so... you have left 3/4 wich accounts for 120 miles...
3/4=120 miles
1/4= 40miles
half of the trip is 160 miles
160 x 2 = 320 the total distance !!!
marking point along, of course following the questions instructions !!
"not draw to scale nor .. nor even close.. but you can have an idea...
l--------------l----l----l----l----l
1st half l l
here she stops
l
l here is 1/4 of the remaing distance...
so... you have left 3/4 wich accounts for 120 miles...
3/4=120 miles
1/4= 40miles
half of the trip is 160 miles
160 x 2 = 320 the total distance !!!
















