Hello,
I have a doubt regarding the following question.
Question: Ata and Carl both departed Townville at noon. Ata travelled by 100 kilometers per hour, and Carl travelled at 75 kilometers per hour. If Ata arrived at Villageton one hour earlier than Carl, what is the distance in kilometers, from Townville to Villageton?
Ata=100km/hr
Carl=75km/hr
carl's time: t
Ata arrived at villageton 1 hour "earlier".Therefore, the total time [t] for ata is = t - 1
Equation 1: (Ata)
D=Rxt
D=100x(T-1)
D=100t-100;
Equation 2: (Carl)
D=Rxt
D=75t
eq1=eq2
75t=100t-100
t=4.
The answer to the above problem is t=3...where am i going wrong?
I have a doubt regarding the following question.
Question: Ata and Carl both departed Townville at noon. Ata travelled by 100 kilometers per hour, and Carl travelled at 75 kilometers per hour. If Ata arrived at Villageton one hour earlier than Carl, what is the distance in kilometers, from Townville to Villageton?
Ata=100km/hr
Carl=75km/hr
carl's time: t
Ata arrived at villageton 1 hour "earlier".Therefore, the total time [t] for ata is = t - 1
Equation 1: (Ata)
D=Rxt
D=100x(T-1)
D=100t-100;
Equation 2: (Carl)
D=Rxt
D=75t
eq1=eq2
75t=100t-100
t=4.
The answer to the above problem is t=3...where am i going wrong?

