I used the Pythagorean theorem to solve this problem, but got the wrong answer!? Please help me solve it, thanks.
Hey SzDave,
Can you show me your method? That should have gotten you the right answer. This has to be a right triangle, because if it's a triangle at all, then AC is a straight line, and it goes through the origin. This means it's a diameter, and any inscribed triangle with one side as the diameter is a right triangle. From there you should be able to use Pythagoras. Only don't forget that AC is the hypotenuse.
So: 1^2 + AB^2 = 2^2
1 + AB^2 = 4
AB^2 = 3
AB = root 3
Area = (b*h)/2 = 1 * (root 3)/2 = (root 3)/2
Make sense?
-t
