Hello all,
Question for you all that comes directly from a Practice Test from MBa.com
Base 2 to the exponent(4-1) to exponent 2
/
Base 2 to the exponent 3-2
Since we have a common base (2) , this questions seems pretty straight forward. We simply have to follow the exponent and pedmas rules to find that exponent (4-1) = 3 x exponent 2 = base 2 to the exponent 6
/
base 2 to the exponent 3-2 which gives us 2 to exponent 1
We are then left with 2 exponent 6
/
2 exponent 1
which gives un 2 exponent 5.
THe official answer is 2 exponent 8 ...... I can see how you get there if you square the first exponent (4-1) , which would be 2 exponent 9/ 2 exponent 1 = 2 exponent 8
but since when do you not multiply an exponent in a bracket by an exponent to that bracket?????
ANy help would be appreciated
Question for you all that comes directly from a Practice Test from MBa.com
Base 2 to the exponent(4-1) to exponent 2
/
Base 2 to the exponent 3-2
Since we have a common base (2) , this questions seems pretty straight forward. We simply have to follow the exponent and pedmas rules to find that exponent (4-1) = 3 x exponent 2 = base 2 to the exponent 6
/
base 2 to the exponent 3-2 which gives us 2 to exponent 1
We are then left with 2 exponent 6
/
2 exponent 1
which gives un 2 exponent 5.
THe official answer is 2 exponent 8 ...... I can see how you get there if you square the first exponent (4-1) , which would be 2 exponent 9/ 2 exponent 1 = 2 exponent 8
but since when do you not multiply an exponent in a bracket by an exponent to that bracket?????
ANy help would be appreciated
