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Area, Members of Club, Candy Manufacturer
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Source: Beat The GMAT — Problem Solving |
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PS 1:
Hence, initial price per ounce of each candy = P/W
After reducing the weight, weight of each candy bar = (W - 20% of W) = 0.8*W
After reducing the weight, price per ounce of each candy bar = P/0.8*W = 5P/4W
Hence, increase in price per ounce of each candy bar = (5P/4W - P/W) = P/4W
Hence, percentage increase in price per ounce of each candy bar = 100*(P/4W)/(P/W) = 100/4 = 25%
The correct answer is E.
Say, initially the weight of each candy was W pounce and price of each candy was P.A certain candy manufacturer reduced the weight of candy bar M by 20 percent but left the price unchanged. what was the resulting percent increase in the price per ounce of the candy bar M?
Hence, initial price per ounce of each candy = P/W
After reducing the weight, weight of each candy bar = (W - 20% of W) = 0.8*W
After reducing the weight, price per ounce of each candy bar = P/0.8*W = 5P/4W
Hence, increase in price per ounce of each candy bar = (5P/4W - P/W) = P/4W
Hence, percentage increase in price per ounce of each candy bar = 100*(P/4W)/(P/W) = 100/4 = 25%
The correct answer is E.
Last edited by Anurag@Gurome on Thu Jun 16, 2011 9:19 pm, edited 1 time in total.
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PS 2:
Then number of different possible selections of the 2 members out of n = nC2
So, nC2 = 190
--> n!/[(n - 2)!*2!] = 190
--> n(n - 1)/2 = 190
--> n(n - 1) = 380
Now we can solve this quadratic for n or we can look for a two-factor factorization of 380 so that the factors are consecutive integer.
As 380 can be expressed as 19*20, n = 20
The correct answer is A.
Say, there are n members.Two members of a club are to be selected to represent the club at a national meeting. if there are 190 different possible selections of the 2 members, how many members does the club have?
Then number of different possible selections of the 2 members out of n = nC2
So, nC2 = 190
--> n!/[(n - 2)!*2!] = 190
--> n(n - 1)/2 = 190
--> n(n - 1) = 380
Now we can solve this quadratic for n or we can look for a two-factor factorization of 380 so that the factors are consecutive integer.
As 380 can be expressed as 19*20, n = 20
The correct answer is A.
Last edited by Anurag@Gurome on Thu Jun 16, 2011 9:20 pm, edited 1 time in total.
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PS 3:
So, s²/S² = 1/2
--> S² = 2s²
--> S = √2s
The correct answer is C.
As the triangles are similar, the ratio of their area will be equal to the ratio of the square of their corresponding sides.In the figures above, if the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S =
So, s²/S² = 1/2
--> S² = 2s²
--> S = √2s
The correct answer is C.
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qduong
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Thank you for the suggestion. I didn't know we could "Search" for the problems and now I do.Anurag@Gurome wrote:Please try to do the following when you're posting questions in this forum...Thanks.
- 1. Do not post more than one question in the same thread.
2. Please take the burden of typing the question instead of posting a screenshot. The forum is not for your benefit only. Make the post searchable.
As for the problems that needed help, I'll type them out so others can search, unless the problems include graphs, figures, or complicated signs.
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