confirm pls?

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magical cook: Master | Next Rank: 500 Posts; Posts: 484; Joined: Sun Jul 30, 2006 7:01 pmFollowed by: 1 member; Thanked: 2 times

by magical cook » Thu Nov 22, 2007 9:56 am

If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x < -14y

I think the answer is B but OA is D -- can anyone confirm?

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Source: Beat The GMAT — Data Sufficiency | Thu Nov 22, 2007 9:56 am

gabriel: Legendary Member; Posts: 986; Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member; Location: India; Thanked: 51 times

Re: confirm pls?

by gabriel » Thu Nov 22, 2007 6:24 pm

magical cook wrote:If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x <14y> a, then 3/7 has to be greater than a ..

So if 1*x is > a then 3/7*x has to be greater than a ..

the first choice says x>y .. so as explained 3/7*x has to be > y .. hence the answer D ..

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ri2007: Master | Next Rank: 500 Posts; Posts: 258; Joined: Mon Aug 27, 2007 12:43 pm; Thanked: 15 times

by ri2007 » Thu Nov 22, 2007 7:21 pm

Gabriel,

Could you pls explain that again?

Thanks in advance

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sujaysolanki: Master | Next Rank: 500 Posts; Posts: 214; Joined: Wed Nov 14, 2007 6:30 am; Thanked: 15 times

by sujaysolanki » Thu Nov 22, 2007 9:02 pm

From stem we need to find is x > 7/3y

From stmt 1 X > y + 4

Pick some numbers to verify ..say
x y = 6,1 or x y = 5 , -2 Conditions holds true Hence knock of BCE left with AD

From stmt 2 is given that x > 14/5y hence it has to > 7/3y

Hence Both are sufficient Hence D

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gabriel: Legendary Member; Posts: 986; Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member; Location: India; Thanked: 51 times

by gabriel » Fri Nov 23, 2007 12:09 am

ri2007 wrote:Gabriel,

Could you pls explain that again?

Thanks in advance

Hey Ri2007

The whole explanation has not showed up due to some posting problem, anyway forget the post the logic I used was not right.

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gabriel: Legendary Member; Posts: 986; Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member; Location: India; Thanked: 51 times

by gabriel » Fri Nov 23, 2007 7:30 am

There does not seem to be a algebraic solution over here, smart substitution is the way forward... while subbing make sure you are covering all possibilities ...

Regards

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sujaysolanki: Master | Next Rank: 500 Posts; Posts: 214; Joined: Wed Nov 14, 2007 6:30 am; Thanked: 15 times

by sujaysolanki » Fri Nov 23, 2007 9:40 pm

My mistake looks like it should be B ...From stmt 1 we dont get a unique answer ..

Btw whats the source of this question

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