There's an old GMATPrep question that is almost identical to this one. Since the value of x can be 3, the quotient can be 0 (when we divide 3 by 11, the quotient is zero and the remainder is 3), so if one of the five answers is right, it has to be E.
Or, if one wants a proper 'proof', then the information in the question tells us x is equal to 11y + 3, and also to 19q + 3 (where q is the quotient when we divide x by 19). So these must equal each other:
11y + 3 = 19q + 3
11y= 19q
But if 11y and 19q are the same number, they must have the same divisors, and since 19 is clearly a divisor of 19q, it must also be a divisor of 11y. It's not a divisor of 11, so it must be a divisor of y, and the remainder is thus zero when we divide y by 19.
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