ollapodrida wrote:Is |x^2+y^2| > |x^2-y^2|?
(1) x > y
(2) x > 0
Alternate approach:
Let a=x² and b=y².
Substituting a=x² and b=y² into the question stem, we get:
|a+b| > |a-b|?
Since each side has absolute value -- implying that each side is NONNEGATIVE -- we can square both sides:
a² + 2ab + b² > a² - 2ab + b²
4ab > 0
ab > 0.
Substituting a=x² and b=y² into the resulting expression, we can rephrase the question stem as follows:
Is x²y² > 0?
When the statements are combined:
It's possible that x=1 and y=0, in which case x²y² = 0.
It's possible that x=2 and y=1, in which case x²y² > 0.
INSUFFICIENT.
The correct answer is
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