Statement 1: There are 12 even integers greater than x and less than yHow many odd integers are greater than the integer x and less than the integer y?
1) There are 12 even integers greater than x and less than y
2) There are 24 integers greater than x and less than y
Case 1: x = 1 and y = 25. Number of odds greater than 1 and less than 25 = 11 (All the odds between 3 and 23 inclusive)
Case 2: x = 1 and y = 26. (Notice there are still 12 even numbers that are greater than 1 and less than 26.) Number of odds greater than 1 and less than 26 = 12. (all the odds between 3 and 25 inclusive.)
Because we can get different results - there could be 11 or 12 odds greater than x and less than y - statement 1 is not sufficient.
Statement 2: There are 24 integers greater than x and less than y. We can use Case 2 again here: x = 1 and y = 26. (There are 24 integers between 2 and 25 inclusive.) We already know there are 12 odds between 1 and 26.
What if x = 2 and y = 27? The number of odds greater than 2 and less than 27 = 12. (All the odds from 3 to 25 inclusive.) No matter what we pick, there will always be exactly 12 odds greater than x and less than y. We have a single unique value. This statement alone is sufficient. The answer is B



















