tracyyahoo wrote:In the xy-plane, what is the x-intercept of the line whose equation is 3y-4x=15?
Method 1:
If we write (3y - 4x = 15) in intercept form we'll get y/(15/3) + x/(-15/4) = 1
Hence, x-intercept = -15/4
Method 2:
The x-intercept is nothing but the x-coordinate of the point where the line cuts the x-axis. Now the y-coordinate of the point must be zero as that point will lie on the x-axis. Thus if we make y = 0 int he given equation, we'll get the value of x-intercept.
3*0 - 4x = 15 ----> x = -15/4
The correct answer is A.
