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PnC;players

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PnC;players

by advita » Fri Jan 14, 2011 6:34 am
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?

23
30
42
60
126

pl explain... thanks.

OA-......60


sorry guys.. easy one.. i got it... 6C3*3C2=60

( i think i shud take rest...)
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by Anurag@Gurome » Fri Jan 14, 2011 7:07 am
advita wrote:9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?

23
30
42
60
126
Number of ways to select 3 guards out of 6 = 6C3 = 20
Number of ways to select 2 forwards out of 3 = 3C2 = 3

Total number of possible different teams = 20*3 = 60

The correct answer is D.
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