INTEGER PROBLEM

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raj_84: Newbie | Next Rank: 10 Posts; Posts: 2; Joined: Wed Jul 09, 2008 10:58 pm

by raj_84 » Sat Jul 12, 2008 3:59 am

IF N IS AN INTEGER AND NOT DIVISIBLE BY 3 OR 4
THEN WHAT MUST (N+SIX))*(N+EIGHT)*(N+TEN) DIVISIBLE BY
1.24
2.32
3.96

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Source: Beat The GMAT — Problem Solving | Sat Jul 12, 2008 3:59 am

sudhir3127: Legendary Member; Posts: 829; Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members; Location: INDIA; Thanked: 84 times

by sudhir3127 » Sat Jul 12, 2008 7:28 am

Nice question... My guess is A. 24 can u tell me whats the OA.

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parallel_chase: Legendary Member; Posts: 1153; Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members; Thanked: 146 times

Re: INTEGER PROBLEM

by parallel_chase » Sat Jul 12, 2008 2:10 pm

raj_84 wrote:IF N IS AN INTEGER AND NOT DIVISIBLE BY 3 OR 4
THEN WHAT MUST (N+SIX))*(N+EIGHT)*(N+TEN) DIVISIBLE BY
1.24
2.32
3.96

My take on this None.

If consider N=2, then it is divisible by all of them,

but If we consider N=5 or -5 it is not divisible by either of them.

Simple reasoning is N could be odd or even. If its even the result could be a multiple of any of the three but if its odd it cannot be a multiple of any of the three.

Whats the OA?

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rs2010: Master | Next Rank: 500 Posts; Posts: 232; Joined: Fri Jul 04, 2008 4:14 pmFollowed by: 1 member; Thanked: 14 times; GMAT Score:760

by rs2010 » Sat Jul 12, 2008 8:28 pm

Since 24=2^3*3,32=2^5,96=2^5*3.

So we will always receive one factor of 3 irrespective of value of N even or odd.

We will not get any factor of 2 when N is odd.

When N is even we will at least receive 3 factors of 2 along with one factor of 3.

So, 24 would be obvious choice.

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parallel_chase: Legendary Member; Posts: 1153; Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members; Thanked: 146 times

by parallel_chase » Mon Jul 14, 2008 7:36 am

hemantsood wrote:Since 24=2^3*3,32=2^5,96=2^5*3.

So we will always receive one factor of 3 irrespective of value of N even or odd.

We will not get any factor of 2 when N is odd.

When N is even we will at least receive 3 factors of 2 along with one factor of 3.

So, 24 would be obvious choice.

I understood the part about the even, but what about when N is odd.

The questions asks MUST BE DIVISIBLE irrespective of odd or even.

It would be nice if you could elucidate on this.

Thanks

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