This is from MGMAT geometry page 22.
If the perimeter of a rectangular flower bed is 30 feet, and its area is 44 square feet, what is the length of each of its shorter sides?
I know how to solve this problem, but i am trying to learn the way MGMAT solves this problem by using the substitution method.
44= l x w => l = (44/w)
30= 2(l + w)
30 = 2 (44/w + w)
I understand up until this part, but then they say to multiply the entire equation by w/2. I don't understand why.
Once they do that they get
15w = 44 + w^2
w^2 - 15w + 44 = 0 I get the quadratic part but how do they make
the jump from the original equation to get the
(w - 11) (w - 4) = 0 15w = 44 + w^2?
Thanks in advance, any input would be greatly appreciated.
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If the perimeter of a rectangular flower bed is 30 feet, and its area is 44 square feet, what is the length of each of its shorter sides?
I know how to solve this problem, but i am trying to learn the way MGMAT solves this problem by using the substitution method.
44= l x w => l = (44/w)
30= 2(l + w)
30 = 2 (44/w + w)
I understand up until this part, but then they say to multiply the entire equation by w/2. I don't understand why.
Once they do that they get
15w = 44 + w^2
w^2 - 15w + 44 = 0 I get the quadratic part but how do they make
the jump from the original equation to get the
(w - 11) (w - 4) = 0 15w = 44 + w^2?
Thanks in advance, any input would be greatly appreciated.
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