BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

rectangle

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 876
Joined: Thu Apr 10, 2008 8:14 am
Thanked: 13 times
by ketkoag » Mon May 04, 2009 4:38 am
A rectangle has the area of 100 and one of its side is x. If its perimeter is equal to the circumference of a circle, in terms of x, what is the area of the circle?
i got an answer that is: [spoiler](100/x + x)^2[/spoiler]
OA is [spoiler](100/x + x)^2 / pi[/spoiler]
please lemme know whether u get my answer coz i doubt that OA is misprinted in the source.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 19
Joined: Tue Jan 09, 2007 5:50 am
Thanked: 1 times

by g2000 » Mon May 04, 2009 6:15 am
area of rectangle = 100
if one side is x --> the other side is 100/x
-> perimeter == 2 ( x + 100/x )

if (perimeter == circumference)
2 (x + 100/x) = 2 * pi * r
pi * r = (x + 100/x)
r = (x + 100/x) * 1/pi

Area of circle = pi * r^2
= pi * ((x + 100/x) * 1/pi ) ^ 2
= 1/pi (x + 100/x) ^ 2
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 83
Joined: Fri May 06, 2011 9:08 am
Thanked: 5 times
GMAT Score:610

by scholardream » Tue May 01, 2012 4:51 pm
I agree with the OA.
The another side is 100/x -> Perimeter of cycle is 2*Pi*r = (100/x+x)*2 -> r = (100/x+x)/Pi
Area of the cycle = Pi*r^2 = Pi*(100/x+x)^2/Pi^2 = (100/x+x)^2/Pi
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1