BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 1223
Joined: Sat Feb 15, 2020 2:23 pmFollowed by: 1 member
by BTGModeratorVI » Wed Jan 06, 2021 8:16 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

Answer: C
Source: official guide
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

Re: If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

by Brent@GMATPrepNow » Wed Jan 06, 2021 10:45 am
BTGModeratorVI wrote: ↑
Wed Jan 06, 2021 8:16 am
 If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

Answer: C
Source: official guide
If 17 integers are negative, then the first 17 integers of the sum look like this: (-17) + (-16) + (-15) + .... (-4) + (-3) + (-2) + (-1)

35 - 17 = 18, so there are still 18 numbers to add to our sum

The next number in the sum is 0, which means the remaining 17 integers must all be positive.
So our sum looks like this: (-17) + (-16) + (-15) + .... (-4) + (-3) + (-2) + (-1) + (0) + 1 + 2 + 3 + . . . + 16 + 17

As we can see, for every NEGATIVE value, we have a POSITIVE value of the same magnitude.
For example we have -16 & 16, and -8 & 8, etc.

When we add each pair (consisting of a NEGATIVE value and the POSITIVE value of the same magnitude), we get 0
For example, (-16) + 16 = 0, and (-7) + 7 = 0

When we do this, our sum reduces to the sum of a bunch of zeros: 0 + 0 + 0 + ..... + 0 + 0

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2545
Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

by swerve » Wed Jan 06, 2021 3:27 pm
BTGModeratorVI wrote: ↑
Wed Jan 06, 2021 8:16 am
 If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

Answer: C
Source: official guide
\(17\) of \(35\) consecutive integers are negative.
\((35 - 17) = 18\) terms left.

The first number after \(-1\) is \(0\).
\((18 - 1) = 17\) terms left: all positive.

\(−17,−16, \ldots,−2,−1,0,1,2,\ldots,16,17\)

The \(17\) negative integers cancel the \(17\) positive integers; the sum of \(34\) of the numbers is \(0\). Add to the remaining number, \(0\).
\((0 + 0) = 0\)

Therefore, C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8155
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

Re: If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

by Scott@TargetTestPrep » Thu Jan 14, 2021 4:32 am
BTGModeratorVI wrote: ↑
Wed Jan 06, 2021 8:16 am
 If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

Answer: C
Source: official guide
Solution:

If 17 of the integers are negative, then the 18th integer is zero, and the remaining 17 integers are positive. Thus, the negative and positive integers cancel out, and the sum is zero.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1