Vincen wrote:What is the probability of rolling two fair dice and having at least one die show an even number?
A. 35/36
B. 3/4
C. 1/2
D. 1/4
E. 1/36
P(at least 1 even number) = 1 - P(2 odd numbers).
Of the 6 numbers on a die, 1/2 are odd, 1/2 are even.
Thus:
P(2 odd numbers) = 1/2 * 1/2 = 1/4.
P(at least 1 even number) = 1 - 1/4 = 3/4.
The correct answer is
B.
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