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Shridharvk
- Junior | Next Rank: 30 Posts
- Posts: 19
- Joined: Wed May 26, 2010 2:26 am
If x^3 -x = p, and x is odd, is p divisible by 24?
This is the answer I found in MGMAT book: -
p= (x-1)x(x+1).
If x is odd, then (x-1) and (x+1) must be even. Thus p is divisible by atleast 4. Futher more, (x-1) and (x+1) are consecutive multiples of 2. So either (x-1) or (x+1) must have another 2 and is therefore divisible by 8.
In addition, one of the number is divisible by 3. Therefore p is divisible by 24.
My question is, if x is odd, then x-1 can be zero also. Why is it mentioned that the minimum value of x-1 is 2?
This is the answer I found in MGMAT book: -
p= (x-1)x(x+1).
If x is odd, then (x-1) and (x+1) must be even. Thus p is divisible by atleast 4. Futher more, (x-1) and (x+1) are consecutive multiples of 2. So either (x-1) or (x+1) must have another 2 and is therefore divisible by 8.
In addition, one of the number is divisible by 3. Therefore p is divisible by 24.
My question is, if x is odd, then x-1 can be zero also. Why is it mentioned that the minimum value of x-1 is 2?












