What is the sum of the digits of the decimal form of the product (2^2009 * 5^2011)?
A. 2
B. 4
C. 5
D. 7
E. 10
A. 2
B. 4
C. 5
D. 7
E. 10
The product = (2^2009)*(5^2011) = (2^2009)*(5^2009)*(5^2) = (10^2009)*(5^2) = 25*(2009 zeroes after 1) = 25000.... (2009 zeroes)diehard_gmat wrote:What is the sum of the digits of the decimal form of the product (2^2009 * 5^2011)?
A. 2
B. 4
C. 5
D. 7
E. 10
Hence, sum of the digits of the product = (2 + 5) = 7
The correct answer is D.
