BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Population

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
MBA Student
Posts: 1194
Joined: Sat Aug 16, 2008 9:42 pmFollowed by: 17 members
Location: Paris, France
Thanked: 71 times
GMAT Score:710
by gmat740 » Mon Jun 15, 2009 8:26 am
A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least population district could have?
A 10700 B 10800 C 10900 D 11000 E 11100


Please provide explanation
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 21
Joined: Fri Jun 12, 2009 2:10 pm
Thanked: 1 times

Re: Population

by jakesing » Mon Jun 15, 2009 9:04 am
How's this sound:

The minimum possible population would be if one district "gave up" an equal chunk to each of the others, such that each of the others is exactly 10% bigger than the sacrificial district. If they were all equal, each district would have 12,000 people. In our situation, each of the 10 receiving ones would have 12,000+x people, and the smallest one would have 12,000-10x people. Then you can set up an equation:

12,000+x=110%*(12,000-10x)=1.1(12,000-10x)

x=100

Now to find the value of the smallest one, you swap it back in:

[spoiler]12,000-10(100)=11,000 and the answer is D[/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 179
Joined: Tue Jan 08, 2008 7:23 pm
Thanked: 11 times
GMAT Score:590

by nitya34 » Mon Jun 15, 2009 9:27 am
Let the least one is X

When other 10 populations have the greatest value, X will have the
minimum value.

X+10*1.1X=132000
get X :)

Good Q, Thanks for posting

I believe source is GMATPrep?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1