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In the xy-coordinate system, like k has y-intercept 12 and an x-intercept greater than zero. If the area of the triangular region enclosed by line k and the two axes is 30, what is the slope of the line k?
A. -12/5
B. -6/5
C. 6/5
D. 3/2
E. 12/5
The OA is A.
Area of triangle = 1/2*b*h
From the prompt, we know 30 = 1/2*b*12 --> Solve: b = 5.
Coordinates of b = (5, 0) and coordinates of h = (0, 12) --> use the slope formula [12-0]/[0-5] = -12/5.
Has anyone another strategic approach to solve this PS question? Regards!
A. -12/5
B. -6/5
C. 6/5
D. 3/2
E. 12/5
The OA is A.
Area of triangle = 1/2*b*h
From the prompt, we know 30 = 1/2*b*12 --> Solve: b = 5.
Coordinates of b = (5, 0) and coordinates of h = (0, 12) --> use the slope formula [12-0]/[0-5] = -12/5.
Has anyone another strategic approach to solve this PS question? Regards!



















