Veritas Quant Question

This topic has expert replies
Source: — Problem Solving |

Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Fri Sep 26, 2014 10:56 am
Location: NYC, LA, Chicago, SF, and Online

by Test Prep Unlimited » Fri Sep 26, 2014 8:44 pm
The prime factorization of 96 is 2^5*3. So since a and b are integers, (ab)^5 must have at least 2^5 and 3^5 as factors. Well, 96 has 2^5 and one 3, so 3^4 is left over (which is y). 3^4=81.

TestPrepUnlimited.com

Legendary Member
Posts: 510
Joined: Thu Aug 07, 2014 2:24 am
Thanked: 3 times
Followed by:5 members

by j_shreyans » Fri Sep 26, 2014 10:28 pm
Hi ,

(ab)^5=96y

We can write 96=2^5X3

So

a^5b^5=2^5 x 3xy

We need four more 3 to equate the equation.

So y=3^4 which is 81

OAD

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Fri Sep 26, 2014 10:33 pm
Hi Fernando,

This question is essentially about prime-factorization - the idea that any positive integer greater than 1 is either prime or the product of a bunch of primes.

Here, we're told that (AB)^5 = 96Y, and that A and B are integers, which means...

(AB)(AB)(AB)(AB)(AB) = 96Y

We can rewrite this as....

(A^5)(B^5) = (2^5)(3)(Y)

We're asked for what Y COULD equal. This means that Y could be MORE than one value...we should start by looking for the smallest value that Y could equal.

Notice how 2^5 could "account for" either A or B, so we need to make sure that the "Y", when combined with the "3" that's already there, could account for the other variable....

If Y = 3^4, then 96Y would = (2^5)(3^5), which gives us two integers raised to the 5th power.

Y COULD = 3^4 = 81

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image