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The number of diagonals of a polygon of \(n\) sides is given by the formula \(d=\dfrac{n(n-3)}2.\) If a polygon has twice as many diagonals as sides, how many sides does it have?
(A) 3
(B) 5
(C) 6
(D) 7
(E) 8
[spoiler]OA=D[/spoiler]
Source: Official Guide
(A) 3
(B) 5
(C) 6
(D) 7
(E) 8
[spoiler]OA=D[/spoiler]
Source: Official Guide
