If \(a > b > 0,\) then \(\sqrt{a^2-b^2}=\)

This topic has expert replies
Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pm
Thanked: 6 times
Followed by:5 members

If \(a > b > 0,\) then \(\sqrt{a^2-b^2}=\)

by Vincen » Sun Aug 15, 2021 12:12 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

If \(a > b > 0,\) then \(\sqrt{a^2-b^2}=\)

A. \(a+b-\sqrt{2ab}\)

B. \(a-b+\sqrt{2ab}\)

C. \(\sqrt{(a-b)^2-2ab}\)

D. \((\sqrt{a+b})(\sqrt{a-b})\)

E. \((\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b})\)

Answer: D

Source: GMAT Prep
Source: — Problem Solving |