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We see that the product of two expressions is 0; for the product to be 0, at least one of the two expressions must be 0. Since x ≠0, the term x - 4 ≠0; thus, (6 + 2/x) must be 0.Gmat_mission wrote:If \(\left(6+\frac{2}{x}\right)\left(x-4\right)=0,\) and \(x\) does not equal \(4\), then \(x =\)
(A) -6
(B) -4
(C) -1/3
(D) 1/3
(E) 3
[spoiler]OA=C[/spoiler]
Source: Magoosh
Since x is not 4, then x - 4 is not zero and hence 6 + 2/x must be 0. Therefore, we have:Gmat_mission wrote:If \(\left(6+\frac{2}{x}\right)\left(x-4\right)=0,\) and \(x\) does not equal \(4\), then \(x =\)
(A) -6
(B) -4
(C) -1/3
(D) 1/3
(E) 3
[spoiler]OA=C[/spoiler]
Source: Magoosh
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