BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Monthly rent for units in a certain apartment building is

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 2276
Joined: Sat Oct 14, 2017 6:10 am
Followed by:3 members

Monthly rent for units in a certain apartment building is

by VJesus12 » Sun Apr 28, 2019 10:11 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Monthly rent for units in a certain apartment building is determined by the formula \(k\cdot \frac{5r^2+10t}{f+5}\) where \(k\) is a constant, \(r\) and \(t\) are the number of bedrooms and bathrooms in the unit, respectively, and \(f\) is the floor number of the unit. A 2-bedroom, 2-bathroom unit on the first floor is going for $800/month. How much is the monthly rent on a 3-bedroom unit with 1 bathroom on the 3rd floor?

(A) $825
(B) $875
(C) $900
(D) $925
(E) $1,000

[spoiler]OA=A[/spoiler]

Source: Manhattan GMAT
Top
Source: — Problem Solving |
Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pm
Thanked: 6 times
Followed by:5 members

by Vincen » Sun Apr 28, 2019 10:37 am
VJesus12 wrote:Monthly rent for units in a certain apartment building is determined by the formula \(k\cdot \frac{5r^2+10t}{f+5}\) where \(k\) is a constant, \(r\) and \(t\) are the number of bedrooms and bathrooms in the unit, respectively, and \(f\) is the floor number of the unit. A 2-bedroom, 2-bathroom unit on the first floor is going for $800/month. How much is the monthly rent on a 3-bedroom unit with 1 bathroom on the 3rd floor?

(A) $825
(B) $875
(C) $900
(D) $925
(E) $1,000

[spoiler]OA=A[/spoiler]

Source: Manhattan GMAT
Hi Vjesus12.

Using this fact
A 2-bedroom, 2-bathroom unit on the first floor is going for $800/month
we can find the value of \(k\), so let's do it.

We have that \(r=2, t=2\) and \(f=1\), so $$800=k\cdot\frac{5\left(2\right)^2+10\cdot2}{1+5}\ \Rightarrow\ 800=k\cdot\frac{40}{6}\ \ \Rightarrow\ k=120.$$ Now, let's compute the monthly rent on a 3-bedroom unit with 1 bathroom on the 3rd floor.

In this case we have that \(r=3, t=1\) and \(f=3\). Then $$Rent=120\cdot\frac{5\left(3\right)^2+10\cdot1}{3+5}\ \Rightarrow\ \ Rent=120\cdot\frac{55}{8}=825.$$ Therefore, the correct answer is the option _A_.

I hope it helps you. <i class="em em-sunglasses"></i>
Top

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8086
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Wed May 01, 2019 4:15 pm
VJesus12 wrote:Monthly rent for units in a certain apartment building is determined by the formula \(k\cdot \frac{5r^2+10t}{f+5}\) where \(k\) is a constant, \(r\) and \(t\) are the number of bedrooms and bathrooms in the unit, respectively, and \(f\) is the floor number of the unit. A 2-bedroom, 2-bathroom unit on the first floor is going for $800/month. How much is the monthly rent on a 3-bedroom unit with 1 bathroom on the 3rd floor?

(A) $825
(B) $875
(C) $900
(D) $925
(E) $1,000

[spoiler]OA=A[/spoiler]

Source: Manhattan GMAT
First we need to determine the value of k, using the following equation based on r = 2, t = 2 and f = 1:

k * [5(2)^2 + 10(2)]/(1 + 5) = 800

k * 40/6 = 800

k = 800 * 6/40

k = 120

Now, using k = 120, r = 3, t = 1 and f = 3, the monthly rent for a 3-bedroom unit with 1 bathroom on the 3rd floor is:

120 * [5(3)^2 + 10(1)]/(3 + 5)

120 * 55/8

15 * 55

825

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Post new topic Post Reply
• Page 1 of 1