Solve

This topic has expert replies
Legendary Member
Posts: 1622
Joined: Thu Mar 01, 2018 7:22 am
Followed by:2 members

Solve

by Gmat_mission » Sun Jun 14, 2020 2:20 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

\(\dfrac{49^3−147}{49}= \)

A. 1654
B. 1977
C. 2045
D. 2398
E. 2401

[spoiler]OA=D[/spoiler]

Source: Veritas Prep
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8086
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

Re: Solve

by Scott@TargetTestPrep » Sat Jun 20, 2020 2:41 pm
Gmat_mission wrote:
Sun Jun 14, 2020 2:20 pm
\(\dfrac{49^3−147}{49}= \)

A. 1654
B. 1977
C. 2045
D. 2398
E. 2401

[spoiler]OA=D[/spoiler]

Solution:

Note that 147 = 49 * 3. Simplifying, we have:

49(49^2 - 3)/49

49^2 - 3

2401 - 3

2398

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage