If a portion of a half water/half alcohol mix is replaced with 25% alcohol solution, resulting in a 30% alcohol solution, what percentage of the original alcohol was replaced?
3
20
66
75
80
e
ANYBODY WITH ALLIGATIONS METHOD FOR THIS ONE. I cant recall how it worked.
ALLIGATIONS GCLUB
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- bblast
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Hi,
concentration of liquid1 = 1/2
concentration of liquid2 = 1/4
concentration of mixture = 3/10
Ratio of volumes of liquid 1:liquid2 = (3/10-1/4) / (1/2-3/10) = (2/40)/(2/10) = 1:4
So, liquid 1 is 20 % of the mixture now. That means 80% of liquid1 is replaced by liquid 2
Hence, E
Cheers!
concentration of liquid1 = 1/2
concentration of liquid2 = 1/4
concentration of mixture = 3/10
Ratio of volumes of liquid 1:liquid2 = (3/10-1/4) / (1/2-3/10) = (2/40)/(2/10) = 1:4
So, liquid 1 is 20 % of the mixture now. That means 80% of liquid1 is replaced by liquid 2
Hence, E
Cheers!
- bblast
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thanks,,,,missed this thing,,clear on aligations again. was a bit rustyFrankenstein wrote:Hi,
So, liquid 1 is 20 % of the mixture now. That means 80% of liquid1 is replaced by liquid 2
!
Cheers !!
Quant 47-Striving for 50
Verbal 34-Striving for 40
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Quant 47-Striving for 50
Verbal 34-Striving for 40
My gmat journey :
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My take on the GMAT RC :
https://www.beatthegmat.com/ways-to-bbla ... 90808.html
How to prepare before your MBA:
https://www.youtube.com/watch?v=upz46D7 ... TWBZF14TKW_