BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

remainder...

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 106
Joined: Wed Mar 23, 2011 4:56 pm
Thanked: 8 times

by seal4913 » Sat Apr 14, 2012 6:57 pm
rattan123 wrote:A number is successively divided by5,6and 8 and leaving remainders 3,4,7 respectively.What will be the remainders if the order of divisors be reversed?
If a number is divided by 5 the remainder is 3, then if the number is divided by 6 the remainder is 4, and if the number is divided by 8 the remainder is 7... is that what you are saying?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Sun Nov 13, 2011 6:19 am

by rattan123 » Sat Apr 14, 2012 7:14 pm
first the number is divided by 5 then the quotient is divided by 6...then the quotient by 8...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 106
Joined: Wed Mar 23, 2011 4:56 pm
Thanked: 8 times

by seal4913 » Sat Apr 14, 2012 7:18 pm
Then how do you get 3 different remainders as stated above.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Sun Nov 13, 2011 6:19 am

by rattan123 » Sat Apr 14, 2012 7:22 pm
lets take an eg....156...divide it by 5 then the remainder is 1 and quotient is 31...then we divide it by 4 then the remainder is 3 and quotient is 7...like this.....the values are different in the question...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 106
Joined: Wed Mar 23, 2011 4:56 pm
Thanked: 8 times

by seal4913 » Sat Apr 14, 2012 7:30 pm
rattan123 wrote:lets take an eg....156...divide it by 5 then the remainder is 1 and quotient is 31...then we divide it by 4 then the remainder is 3 and quotient is 7...like this.....the values are different in the question...
This is not a gmat question.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 210
Joined: Thu Mar 08, 2012 11:24 pmFollowed by: 3 members
Thanked: 62 times

by niketdoshi123 » Sat Apr 14, 2012 9:21 pm
are the remainders 1,5,4???
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 134
Joined: Fri Apr 06, 2012 3:11 amFollowed by: 5 members
Thanked: 35 times

by Shalabh's Quants » Sat Apr 14, 2012 10:00 pm
rattan123 wrote:A number is successively divided by5,6and 8 and leaving remainders 3,4,7 respectively.What will be the remainders if the order of divisors be reversed?
say in 3rd & last cycle, the quotient from II cycle is divided by 8 and leaves K as quotient and 7 as remainder, then the Dividend(quotient of II) will be 8K+7.

Similarly,from 2nd cycle,as quotient is 8K+7. It means Dividend of II(quotient of I)will be 6*(8k+7)+4 = 48K+46.

Similarly, as quotient in I cycle is 48K+46. It means Dividend of I cycle will be 5*(48K+46)+3= 240k+233.

So finally the nos. is 240k+233. Lets put a convenient value of k....say k=1.

then the rqd.no. will be N=240*1+233 = 473.

Now Reverse division...

1. 473/8 => quotient = 59; remainder = 1.

2. 59/6 => quotient = 9; remainder = 5.

3. 9/5 => quotient = 1; remainder = 4.

Remainder will be 1, 5, 4.
Shalabh Jain,
e-GMAT Instructor
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1