99 can be expressed as 9*11 and ((9*11)^x-(9*11)^y)/100 is what interests us
9 raised to the different powers returns a unit's digits 1 or 9; 9 or 1 multiplied by 11 raised to any power remain their values
thus, the remainders can be 0 (or no remainder), 98, 1 resuming with 2 remainders
a
[spoiler]
my only concern is we are asked to find the types of remainders and not actual remainders, because 0 is when we have no remainder, but i include this in my final answer. Without 0 we have two types of remainders, with 0 we have 3 types.[/spoiler]
Fundamental
This topic has expert replies
Source: Beat The GMAT — Problem Solving |
- rijul007
- Legendary Member
- Posts: 588
- Joined: Sun Oct 16, 2011 9:42 am
- Location: New Delhi, India
- Thanked: 130 times
- Followed by:9 members
- GMAT Score:720
LalaB wrote:pemdas, I didnt get it
lets assume x=3 y =2, then -
11(9^3-9^2)/100 =11*9^2*8/100=7128/100
according to ur answer choice, what is the remainder of 7128/100?
check it again.. do you see what blunder you've done?
- LalaB
- Master | Next Rank: 500 Posts
- Posts: 425
- Joined: Wed Dec 08, 2010 9:00 am
- Thanked: 56 times
- Followed by:7 members
- GMAT Score:690
oh i crijul007 wrote:LalaB wrote:pemdas, I didnt get it
lets assume x=3 y =2, then -
11(9^3-9^2)/100 =11*9^2*8/100=7128/100
according to ur answer choice, what is the remainder of 7128/100?
check it again.. do you see what blunder you've done?
9^2*11^2(9*11-1)/100=98*9^2*11^2/100
- rijul007
- Legendary Member
- Posts: 588
- Joined: Sun Oct 16, 2011 9:42 am
- Location: New Delhi, India
- Thanked: 130 times
- Followed by:9 members
- GMAT Score:720
Divide 99 by 100 you get -1 or 99 as a remainder
99^x/100 => -1^x would be the ramainder
99^y/100 => -1^y would be the remainder
(99^x+99^y)/100 => remainder (-1)^x - (-1)^y
when x and y are even
remainder = 1-1 = 0
when x is even and y is odd
remainder = 1-(-1) = 2
when x is odd and y is even
remainder = -1-1 = -2 or 98
when x and y are odd
remainder = -1-(-1) = 0
Number of different types of remainder = 3 {-2,0,2}
Option A
99^x/100 => -1^x would be the ramainder
99^y/100 => -1^y would be the remainder
(99^x+99^y)/100 => remainder (-1)^x - (-1)^y
when x and y are even
remainder = 1-1 = 0
when x is even and y is odd
remainder = 1-(-1) = 2
when x is odd and y is even
remainder = -1-1 = -2 or 98
when x and y are odd
remainder = -1-(-1) = 0
Number of different types of remainder = 3 {-2,0,2}
Option A
- santhoshsram
- Senior | Next Rank: 100 Posts
- Posts: 62
- Joined: Wed Oct 26, 2011 2:30 pm
- Thanked: 7 times
- santhoshsram
- Senior | Next Rank: 100 Posts
- Posts: 62
- Joined: Wed Oct 26, 2011 2:30 pm
- Thanked: 7 times
I didn't quite follow this part, remainder -1 when 99 is divided by 100. Can you please explain.rijul007 wrote:Divide 99 by 100 you get -1 or 99 as a remainder
-- Santhosh S












