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the three digit pos

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Source: — Data Sufficiency |
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by tohellandback » Wed Aug 05, 2009 10:34 pm
IMO B

N = a2b, where N is a multiple of 3 and a multiple of 5
so b must be 5 or 0


1)a+b is an even integer
when b=5, a=5
when b=0, a =4
not sufficient

2)a/b=1
in this case b not equal to 0. so b must be 5 and hence a must be 5
N is 525
sufficient
The powers of two are bloody impolite!!
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by ram_raj » Thu Aug 06, 2009 3:22 am
IMO B.

Agree with the above explanation .
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by baha777 » Thu Aug 06, 2009 9:15 am
Definitely "B".
Since "5" has less multiples available in 3 digit integer, lets choose "5" to test. 5 has multiple integers that end with either 0 or 5. With the statement 2 showing first and third digit in the 3-digit integer being the same, once you test (121, 222, 323, 424, 525, 626, 727, 828 and 929), only 525 has both factors of 3 and 5.
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by tj123 » Thu Aug 06, 2009 8:25 pm
OA is B
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