Probability of A attending class is 1/6 ,probability of B attending class is 1/5 . What is the probability that either A alone or B alone attends class?
1/10
1/5
3/10
1/3
11/30
1/10
1/5
3/10
1/3
11/30
Since p(A)+p(B)>1 we infer the events A and B are not mutually exclusive, i.e. there's possibility that p(A&B)=p(A)*p(B) is there.abhilashsiyer wrote:Probability of A attending class is 1/6 ,probability of B attending class is 1/5 . What is the probability that either A alone or B alone attends class?
1/10
1/5
3/10
1/3
11/30
Thus, p(A)+p(B)-p(A)*p(B)=p(A or B), 1/6 + 1/5 - 1/30 = (5+6-1)/30 = 10/30 = 1/3
