the question is wrongern5231 wrote:Is x^2+x>-y^2?
(1) x^2+y^2=1
(2) x>0
x^2+x>-y^2
-(x^2+x)<y^2 is sure no need for either statments.
plz revise and re post
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
inqeualities ds
Source: Beat The GMAT — Data Sufficiency |
x^2+x>-y^2
-(x^2+x)<y^2 is sure no need for either statments.
plz revise and re post
ya how did you conclude that?
What if x = -0.1...then x^2 = 0.01
therefore: x^2 + x = 0.01-0.1 = -0.09
If: y=0.4, y^2 = 0.16..therefore: -(y^2) = -0.16
Therefore: x^2+x > -(y^2)
Anyway IMO:
Answer is B
What if x = -0.1...then x^2 = 0.01
therefore: x^2 + x = 0.01-0.1 = -0.09
If: y=0.4, y^2 = 0.16..therefore: -(y^2) = -0.16
Therefore: x^2+x > -(y^2)
Anyway IMO:
Answer is B
IMO B
from (1), -1<=x<=1
is x^2 + x > -y^2
1 - y^2 + x > -y^2 if -1 < x <= 1
1 - y^2 + x = -y^2 if x = -1
INSUF
from (2), x > 0
x^2 + x > 0 > -y^2
SUFF
from (1), -1<=x<=1
is x^2 + x > -y^2
1 - y^2 + x > -y^2 if -1 < x <= 1
1 - y^2 + x = -y^2 if x = -1
INSUF
from (2), x > 0
x^2 + x > 0 > -y^2
SUFF
-
PussInBoots
- Master | Next Rank: 500 Posts
- Posts: 157
- Thanked: 3 times
x^2+x>-y^2 <=> x^2 + y^2 + x > 0?
(1) x^2+y^2=1
INSUFF, with x = -1, y = 0, the equation is exactly 0
(2) x>0
SUFF
(B)
(1) x^2+y^2=1
INSUFF, with x = -1, y = 0, the equation is exactly 0
(2) x>0
SUFF
(B)
