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formula V= 1/(2r)^3

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by sibbineni » Sat Aug 09, 2008 11:23 am
just plugin values to make easy

if r=1
then V = 1/(2x1)^3 = 1/2^3 = 1/8

r= 1/2 given

V = 1/(2 x 1/2)^3 = 1/1^3 = 1/1 = 1

Thus V is multiplied by 8: 1/8 x 8 = 1

B

(or)

V=1/(2r)^3=1/8*r^3

r=r/2

then

V=1/r^3

in order to get V original value V must be multiplied by 8


ie
8V=1/r^3

V=1/8*r^3 (Original value)
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Master | Next Rank: 500 Posts
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by beater » Sat Aug 09, 2008 11:49 am
So, is the question really asking, what does r need to be mutiplied by to retain the orignial value when r is halved??? Thanks for your help!
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